Solutions to Chapter 19 Additional rules for TFL

A. The following proofs are missing their citations (rule and line numbers). Add them wherever they are required:

Line number

Subproof level

Formula

Justification

1

0
W→¬B

2

0
A∧W

3

0
B∨(J∧K)

4

0
W
∧E 2

5

0
¬B
→E 1, 4

6

0
J∧K
DS 3, 5

7

0
K
∧E 6

Line number

Subproof level

Formula

Justification

1

0
L↔¬O

2

0
L∨¬O

3

open subproof, 1
¬L

4

1
¬O
DS 2, 3

5

1
L
↔E 1, 4

6

1
⊥
¬E 5, 3

7

close subproof, 0
¬¬L
¬I 3–6

8

0
L
DNE 7

Line number

Subproof level

Formula

Justification

1

0
Z→(C∧¬N)

2

0
¬Z→(N∧¬C)

3

open subproof, 1
¬(N∨C)

4

1
¬N∧¬C
DeM 3

5

1
¬N
∧E 4

6

1
¬C
∧E 4

7

open subproof, 2
Z

8

2
C∧¬N
→E 1, 7

9

2
C
∧E 8

10

2
⊥
¬E 9, 6

11

close subproof, 1
¬Z
¬I 7–10

12

1
N∧¬C
→E 2, 11

13

1
N
∧E 12

14

1
⊥
¬E 13, 5

15

close subproof, 0
¬¬(N∨C)
¬I 3–14

16

0
N∨C
DNE 15

B. Give a proof for each of these arguments:

  1. 1.
    ​

    E∨F, F∨G, ¬F∴E∧G

    Line number

    Subproof level

    Formula

    Justification

    1

    0
    E∨F

    2

    0
    F∨G

    3

    0
    ¬F

    4

    0
    E
    DS 1, 3

    5

    0
    G
    DS 2, 3

    6

    0
    E∧G
    ∧I 4, 5
  2. 2.
    ​

    M∨(N→M)∴¬M→¬N

    Line number

    Subproof level

    Formula

    Justification

    1

    0
    M∨(N→M)

    2

    open subproof, 1
    ¬M

    3

    1
    N→M
    DS 1, 2

    4

    1
    ¬N
    MT 3, 2

    5

    close subproof, 0
    ¬M→¬N
    →I 2–4
  3. 3.
    ​

    (M∨N)∧(O∨P), N→P, ¬P∴M∧O

    Line number

    Subproof level

    Formula

    Justification

    1

    0
    (M∨N)∧(O∨P)

    2

    0
    N→P

    3

    0
    ¬P

    4

    0
    ¬N
    MT 2, 3

    5

    0
    M∨N
    ∧E 1

    6

    0
    M
    DS 5, 4

    7

    0
    O∨P
    ∧E 1

    8

    0
    O
    DS 7, 3

    9

    0
    M∧O
    ∧I 6, 8
  4. 4.
    ​

    (X∧Y)∨(X∧Z), ¬(X∧D), D∨M ∴M

    Line number

    Subproof level

    Formula

    Justification

    1

    0
    (X∧Y)∨(X∧Z)

    2

    0
    ¬(X∧D)

    3

    0
    D∨M

    4

    open subproof, 1
    X∧Y

    5

    1
    X
    ∧E 4

    6

    close subproof, open subproof, 1
    X∧Z

    7

    1
    X
    ∧E 6

    8

    close subproof, 0
    X
    ∨E 1, 4–5, 6–7

    9

    open subproof, 1
    D

    10

    1
    X∧D
    ∧I 8, 9

    11

    1
    ⊥
    ¬E 10, 2

    12

    close subproof, 0
    ¬D
    ¬I 9–11

    13

    0
    M
    DS 3, 12